A force of 20 N acts on an elastic spring. The resort elongates 5 cm. What will be the elongation of the spring if the force is twice as big. But if the force would be 5 times higher?

A force of 20 N acts on an elastic spring. The resort elongates 5 cm. What will be the elongation of the spring if the force is twice as big. But if the force would be 5 times higher?


Solution

We know from the measurement of force that there is direct proportionality between the value of the spring's elongation and the force that deforms it, and is result that:



For force F1 = 20 N:

Δl1 = 5 cm


For 2 times higher force:


F2 = 2 * 20 N = 40 N =>

Δl2 = 2 * Δl1 = 2 * 5 cm = 10 cm



For 5 times higher force:


F5 = 5 * 20N = 100 N =>

Δl₅ = 5 * Δl₁ = 5 * 5 cm = 25 cm

Mechanics

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