We have a fully filled glass jar with 1 kg of mercury. If you empty the jar, you can put 1 kg of water in it?
Solution
The volume represents how much space a substance in our case occupies in m3 (cubic meters).
We calculate the volume for each substance based on density and find out if the volume occupied by 1 kg of mercury is the same as the volume occupied by 1 kg of water.
We use the substance density formula:
ρ = m / V
we know the density for each substance from the table with densities and the mass that is 1 kg and we find the volume for each of them:
V = m / ρ
The volume occupied by 1 kg of mercury:
V = 1kg / ρ
V = 1kg / 13.600 kg / m3
Vmercury = 0,000074 m3
The volume occupied by 1 kg of water:
V = 1kg / ρ
V = 1 kg / 1000 kg / m3
Vwater = 0.0001 m3
Vwater > Vmercury
So, 1 Kg of water occupies more space than 1 kg of mercury.
In our case 1 kg of water will not enter in the jar in which was 1 kg of mercury.
Legend
m = mass (kg)
V = volume (m3)
ρ = density (kg / m3)
Mechanics
Physics problems with solutions
Solution
The volume represents how much space a substance in our case occupies in m3 (cubic meters).
We calculate the volume for each substance based on density and find out if the volume occupied by 1 kg of mercury is the same as the volume occupied by 1 kg of water.
We use the substance density formula:
ρ = m / V
we know the density for each substance from the table with densities and the mass that is 1 kg and we find the volume for each of them:
V = m / ρ
The volume occupied by 1 kg of mercury:
V = 1kg / ρ
V = 1kg / 13.600 kg / m3
Vmercury = 0,000074 m3
The volume occupied by 1 kg of water:
V = 1kg / ρ
V = 1 kg / 1000 kg / m3
Vwater = 0.0001 m3
Vwater > Vmercury
So, 1 Kg of water occupies more space than 1 kg of mercury.
In our case 1 kg of water will not enter in the jar in which was 1 kg of mercury.
Legend
m = mass (kg)
V = volume (m3)
ρ = density (kg / m3)
Mechanics
Physics problems with solutions
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