A steel cylinder has 25 mm in diameter and 1 m height. What is its mass?
We know
ρ = 7800 kg / m3 (steel density)
d = 25 mm
h = 1 m
m =?
Solution
V cylinder = πR2h
ρ = 7800 kg / m3 = 7.8 g / cm3
ρ = m / V
m = ρ x V
m = 7800 kg / m3 x x (d / 2)2 x h
m = 7800 kg / m3 x 3.14 x (25 mm / 2)2 x 1 m
m = 7800 kg / m3 x 3.14 x 156.25 mm x 100 cm
m = 7.8 g / cm3 x 3.14 x 15.625 cm2 x 100 cm
m = 7.8 g / cm3 x 3.14 x 1562.5 cm3
m = 7.8 g x 3.14 x 1562.5
m = 0.0078 mg x 3.14 x 1562.5
m = 38.27 mg
Legend
m = mass
ρ = density
V = volume
h = height
d = diameter
Mechanics
Physics problems with solutions
We know
ρ = 7800 kg / m3 (steel density)
d = 25 mm
h = 1 m
m =?
Solution
V cylinder = πR2h
ρ = 7800 kg / m3 = 7.8 g / cm3
ρ = m / V
m = ρ x V
m = 7800 kg / m3 x x (d / 2)2 x h
m = 7800 kg / m3 x 3.14 x (25 mm / 2)2 x 1 m
m = 7800 kg / m3 x 3.14 x 156.25 mm x 100 cm
m = 7.8 g / cm3 x 3.14 x 15.625 cm2 x 100 cm
m = 7.8 g / cm3 x 3.14 x 1562.5 cm3
m = 7.8 g x 3.14 x 1562.5
m = 0.0078 mg x 3.14 x 1562.5
m = 38.27 mg
Legend
m = mass
ρ = density
V = volume
h = height
d = diameter
Mechanics
Physics problems with solutions
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