Two electric point charges of equal size are 15 cm apart and interact with a force of 8.1 N ...

Two electric point charges of equal size are 15 cm apart and interact with a force of 8.1 N. What is the modulus of these charges?

Solution

The modulus of the electric charges can be calculated using Coulomb's law: 

F = k * q1 * q2 / d^2

where: 

F is the interaction force

k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2)

q1 and q2 are the values of the point charges, and d is the distance between them.

If we solve this equation for q1 and q2, we get: 

q1 = q2 = sqrt(F * d^2 / k) = sqrt(8.1 N * (0.15 m)^2 / 8.99 x 10^9 N * m^2 / C^2) = 8.98 x 10^-19 C.

So, the modulus of the charges is approximately 8.98 x 10^-19 C.

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