Solution
Let's consider the Earth as a sphere with a radius of 6.371 x 10^6 meters, and the Sun as a sphere with a radius of 6.99 x 10^8 meters.
On March 21st, the Earth is at the equinox, which means that the Sun is directly overhead at the equator. The distance between the center of the Earth and the center of the Sun is 1.5 x 10^11 meters.
The apparent size of the Sun as seen from the Earth is about 0.5 degrees. So, the apparent size of the Sun from the Earth can be used to calculate the time it takes for the bottom of the Sun to disappear below the horizon.
Time = (2 * (Earth's radius + Sun's radius) * sin(Sun's apparent size / 2)) / (speed of light)
Plugging in the numbers, we get:
Time = (2 * (6.371 x 10^6 + 6.99 x 10^8) * sin(0.5 / 2)) / (3 x 10^8)
Time = (2 * (6.371 x 10^6 + 6.99 x 10^8) * 0.25) / (3 x 10^8)
Time = (2 * (7.0061 x 10^8) * 0.25) / (3 x 10^8)
Time = (1.7015 x 10^8) / (3 x 10^8)
Time = 0.567 seconds
So, it takes approximately 0.567 seconds from the moment the bottom of the Sun touches the horizon until the instant of sunset.
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