Two infinite sheets sheets A and B are separated by a distance d=30 m. If the charge density is a=-a=10 nc / m^2. Find the potential difference between the sheets. The value of the Energy required?
Solution
The potential difference between the two infinite sheets can be calculated using Coulomb's law as follows:
V = k * Q / d
Where k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2), Q is the charge on each sheet (Q = a * A, where A is the area of each sheet), and d is the distance between the sheets.
Plugging in the values, we get:
V = 8.99 x 10^9 * (10^-9 * A) / 30 V = 0.3 V
The energy required to move a positive test charge from one sheet to the other can be calculated using the potential difference as follows:
E = q * V
Where:
q is the test charge
V is the potential difference between the sheets.
Assuming a test charge of 1 C, we get:
E = 1 * 0.3 E = 0.3 J
Therefore, the potential difference between the sheets is 0.3 V and the energy required to move a positive test charge of 1 C from one sheet to the other is 0.3 J.
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